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+1 vote
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in Physics by (19.5k points)

The correct expression for Bernoulli’s theorem is (symbols have their usual meaning)

(1) \(P+ \rho{gh}+\frac{1}{2}\rho{v}^2\) = constant 

(2) \(P+ \frac{1}{2}\rho{gh}+\frac{1}{2}\rho{v}^2\) = constant

(3) P + \(\rho{gh}+\frac{1}{2}\rho{v}^2\) = constant

(4) P + \(2\rho{gh}+\rho{v}^2\) = constant

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1 Answer

+1 vote
by (20.3k points)

Correct Option is (1) P +\(\rho{gh}+\frac{1}{2}\rho{v}^2\) = constant 

According to Bernoulli’s theorem 

P +\(\rho{gh}+\frac{1}{2}\rho{v}^2\) = constant

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