Correct answer is : 5
\(\mathrm{i}=\mathrm{K} \theta\)
\(\frac{2}{\mathrm{G}+\mathrm{R}}=\mathrm{K} \theta\)
\(\Rightarrow \frac{1}{\theta}=\frac{(\mathrm{G}+\mathrm{R}) \mathrm{K}}{2}=\mathrm{R}\left(\frac{\mathrm{K}}{2}\right)+\frac{\mathrm{KG}}{2}\)
Slope \( =\frac{\mathrm{K}}{2}=\frac{1}{4} \Rightarrow \mathrm{K}=0.5=5 \times 10^{-1} \mathrm{~A}\)