Correct option is (5) none of these
\(f(x)=\frac{x^2+2 x-15}{x^2-4 x+9}\)
\(f^{\prime}(x)=\frac{\left(x^2-4 x+9\right)(2 x+2)-\left(x^2+2 x-15\right)(2 x-4)}{\left(x^2-4 x+9\right)^2}\)
\(f^{\prime}(x)=\frac{-6 x^2+48 x-42}{\left(x^2-4 x+9\right)^2}\)
So f'(x) is +ve & -ve so many one and into