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oxygen atoms to bromine atoms\(\xrightarrow {HNO_3 .H_2SO_4} \underset {major\, product}{P} \xrightarrow {2\,Br_2, Fe} \underset {major\,product}{Q}\)

The ratio of number of oxygen atoms to bromine atoms in the product Q is _____ \(\times 10 ^{-1}.\)

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Correct answer is : 15

number of oxygen atoms to bromine atoms

In Q Total oxygen atoms = 3 

Total Bromine atoms = 2

ration \(= \frac {3}{2} = 1.5 \times 10 ^{-1}\)

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