Correct option is : (4) 1
\(
\because \ \mathrm{E} \propto \frac{\mathrm{z}^2}{\mathrm{n}^2}
\)
Energy of the \(2^{\text {nd }}\) orbit
\(
\begin{aligned}
& =\frac{-13.6}{4}=-3.4 \mathrm{eV}
\end{aligned}
\)
\(
\begin{aligned}
& \Delta \mathrm{E}_{2.1}=10.2 \mathrm{eV}
\end{aligned}
\)
So, only possible transition is from
\(
\mathrm{n}=2 \text { to } \mathrm{n}=1
\)