Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
631 views
in Physics by (49.7k points)
closed by

The magnetic field in a plane electromagnetic wave is \(\mathrm{B}_{\mathrm{y}}=\left(3.5 \times 10^{-7}\right) \sin \left(1.5 \times 10^{3} \mathrm{x}+0.5\right.\) \(\left.\times 10^{11} \mathrm{t}\right) \mathrm{T}\). The corresponding electric field will be

(1) \(\mathrm{E}_{\mathrm{y}}=1.17 \sin \left(1.5 \times 10^{3} \mathrm{x}+0.5 \times 10^{11} \mathrm{t}\right) \mathrm{Vm}^{-1}\)

(2) \(\mathrm{E}_{\mathrm{z}}=105 \sin \left(1.5 \times 10^{3} \mathrm{x}+0.5 \times 10^{11} \mathrm{t}\right) \mathrm{Vm}^{-1}\)

(3)\( \mathrm{E}_{\mathrm{z}}=1.17 \sin \left(1.5 \times 10^{3} \mathrm{x}+0.5 \times 10^{11} \mathrm{t}\right) \mathrm{Vm}^{-1}\)

(4) \(E_{y}=10.5 \sin \left(1.5 \times 10^{3} \mathrm{x}+0.5 \times 10^{11} \mathrm{t}\right) \mathrm{Vm}^{-1}\)  

1 Answer

+1 vote
by (46.4k points)
selected by
 
Best answer

Correct option is :  (2) \(\mathrm{E}_{\mathrm{z}}=105 \ \sin \left(1.5 \times 10^{3} \mathrm{x}+0.5 \times 10^{11} \mathrm{t}\right) \mathrm{Vm}^{-1}\)  

\(\mathrm{E}_{0}=\mathrm{B}_{0} \mathrm{C}\)

\(\mathrm{E}_{0}=3 \times 10^{8} \times\left(3.5 \times 10^{-7}\right) \sin \left(1.5 \times 10^{3} \mathrm{x}+0.5 \times 10^{11} \mathrm{t}\right)\)

\(\mathrm{E}_{0}=105 \ \sin \left(1.5 \times 10^{3} \mathrm{x}+0.5 \times 10^{11} \mathrm{t}\right) \mathrm{Vm}^{-1}\)

Data inconsistent while calculating speed of wave. You can challenge for data.  

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...