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4 सेमी त्रिज्या का पारे का गोला बनाने में किया गया कार्य बराबर होगा (पारा का पृष्ठ तनाव = 0.465 N/m)

(A) \(7.03 \times 10^{-3}\) joule

(B) \(10\times 10^{-2}\) joule

(C) \(9.35 \times 10^{-3}\) joule

(D) \(18.68 \times 10^{-3}\) joule

1 Answer

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Best answer

सही विकल्प है (C) \(9.35 \times 10^{-3}\) joule

हम जानते हैं कि,

किया गया कार्य = पृष्ठ तनाव × पृष्ठ क्षेत्रफल

\(= 0.465 \times 4 \pi r^2\)

\(= 0.465 \times 4\pi(4 \times 10^{-2})^2\)

\(= 0.465 \times 4\pi\times 16\times 10^{-4}\)

\(= 0.465\times64\pi \times 10^{-4}\)

\(=29.76\pi \times 10^{-4}\)

\(=93.446 \times 10^{-4}\)

\(=9.35 \times 10^{-3} \) J

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