Correct option is (B) P-5, Q-3, R-2, S-4
\(XeF_2 \Rightarrow 2\) sigma bonds and 3 lone pairs on Xe, number of hybrid orbitals = 5, \(sp^3 d\) hybridisation , geometry will be trigonal bipyramidal.
P–5
\(XeF_4 \Rightarrow 4\) sigma bonds and 2 lone pairs on Xe, number of hybrid orbitals = 6, \(sp^3 d^2\) hybridisation , geometry will be octahedral.
Q–3
\(XeO_3 \Rightarrow 3\) sigma bonds and 1 lone pairs on Xe, number of hybrid orbitals = 4, \(sp^3\) hybridisation , geometry will be tetrahedral.
R–2
\(XeO_3F_2 \Rightarrow 5\) sigma bonds and 0 lone pairs on Xe, number of hybrid orbitals = 5, \(sp^3 d\) hybridisation , geometry will be trigonal bipyramidal.
S–4