Capacitance A has higher capacitance. Since capacitance C = \(\frac{Q}{V}\) and here the slope of the graph is given by \(\frac{V}{Q}\) (i.e. \(\frac{1}{C}\)). Hence capacitance is given by reciprocal of slope V - Q graph. As slope of capacitor A is less than that of capacitor B. Hence the capacitance of capacitor A is higher.