Since capacitance of a capacitor is given by
C = \(\frac{\varepsilon_0A}{d}\)
Here d is the same for both the capacitors.
So C ∝ A
As area of C2 = 2 x Area of C1
∴ C2 = 2 C1
Also C = \(\frac{q}{V}\).
Thus the slope of q -V graph gives the value of capacitance. Here slope for A is greater than B, hence graph A corresponds to C2 and graph B corresponds to C1.