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An alternating voltage E = E0 sin ωt is applied to a circuit containing a resistor R connected in series with a black box. The current in the circuit is found to be I = I0 sin (ωt + \(\frac{\pi}{4}\)).

An alternating voltage

(i) State whether the element in the black box is a capacitor or inductor.

(ii) Draw the corresponding phasor diagram and find the impedance in terms of R.

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(i) Here we find that the current leads the voltage by a phase \(\frac{\pi}{4}\), so the element in the black box is a capacitor.

(ii) Phasor diagram is shown in fig. 

Phasor diagram

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