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ago in Mathematics by (30.9k points)
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A 60% तथा B 90% सत्य बोलता है, तो किसी एक ही तथ्य पर दोनों में विरोधाभास होने की क्या प्रतिशतता है ?

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p(विरोधाभास) \(=p\left(\mathrm{A}_{\mathrm{F}}\right) p\left(\mathrm{B}_{\mathrm{T}}\right)+p\left(\mathrm{A}_{\mathrm{T}}\right) \times p\left(\mathrm{B}_{\mathrm{F}}\right)\)

\(=\frac{40}{100} \times \frac{50}{100}+\frac{600}{100} \times \frac{10}{100}=\frac{20}{100}+\frac{6}{100}=\frac{26}{100} \)

\( \Rightarrow\) p(सत्य) \(=\frac{40}{100} \times \frac{90}{100}+\frac{60}{100} \times \frac{10}{100}=\frac{36}{100}+\frac{6}{100}\)

p(विरोधाभास) \(=\frac{36}{100}+\frac{6}{100}=\frac{42}{100}=0.42 \%\)

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