Question

Kinetic energies of two particles of masses m and 2 m are same, then ratio of their linear moments will be:

(a) 1

(b) 1/2

(c) 1/V²

(d) 2

Answer 1

Correct option is : (c) 1/V²

Linear momentum p = \(\sqrt{2mK}\)

∵ K₁ = K₂ = K; m₁ = m; m₂ = 2m

\(\therefore\ \frac{p_1}{p_2} = \sqrt{\frac{2m_1K}{2m_2K}} =\sqrt{\frac{m_1}{m_2}} = \sqrt{\frac{m}{2m}} = \frac{1}{\sqrt{2}}\)

p₁ : p₂ = 1 : \(\sqrt{2}\)

Hence, option (c) is correct.