Conversion of volume (100 lit.) of gas at 20° C and 2 atm. pressure to NTP
At given conditions
\(V_1= 100\ litres\)
\(P_{1} = 2\ atm\)
\(T_{1} = 20 + 273 = 293A\)
Αt Ν.Τ.Ρ.
\(V_{2} =\)
\(P_{2} = 1\ atm\)
\(T_{2} = 273A\)
Applying the formula,
\(\frac{(P_{1}V_{1})}{T_{1}} = \frac{(P_{2}V_{2})}{T_{2}}\)
\(V_2 = \frac{P_1V_1}{T_1} \times \frac{T_2}{P_2} \)
\(= \frac{2 \times 100 \times 273}{293 \times 1} = 186.3 \ lit.\)
Calculation of weight of 186.3 litres of \(H_{2}S\)
22.4 litres of \(H_{2}S\) at NTP weigh 34 g
186.3 litres of \(H_{2}S\) at NTP weigh = \(\frac{34}{22.4} \times 186.3 = 282.78\) gm
Alternatively,
\(m = \frac{PVM}{RT}\)
Substituting the various values,
\(m = \frac{2\times 100 \times 34}{0.0821 \times 293}\)
\(= 282.68 g\)
