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If the weight of 5.6 litres of a gas at N.T.P. is 11 gram. The gas may be

(a) PH3

(b) COCl2

(c) NO

(d) N2O

1 Answer

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Correct option is (d) N2O

Volume occupied by 1 mole of gas = 22.4 litres.

Moles of gas = \(\frac{5.6}{22.4}\) = 0.25

Since, 0.25 moles weigh 11 gram, 1 mole will weigh 44 grams.

Therefore, we need a gas whose molar mass is 44 grams.

Hence, N2O.

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