Question

A sample of gas occupies 100 ml at 27°C and 740 mm pressure. When its volume is changed to 80 ml at 740 mm pressure, the temperature of the gas will be

(a) 21.6°C

(b) 240°C

(c) -33°C

(d) 89.5°C

Answer 1

Correct option is (c) -33°C

Given :

V₁ = 100mL,T₁ = 27^∘C = 300K.

P₁ = 740

V₂ = 80mL, T₂ = ?

P₂ = 740mm

We know, \(\frac{V_1}{T_1} = \frac{V_2}{T_2}\)

\(\therefore T_2 = \frac{V_2 \times T_1}{V_1} = \frac{80 \times 300}{100} = 240 K\)

\(T_2 = -33^\circ C\)