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A sample of a given mass of a gas at a constant temperature occupies 95 cm3 under a pressure of 9.962 x 104 Nm-2. At the same temperature its volume at a pressure of 10.13 x 104 Nm-2 is

(a) 190 cm3

(b) 93 cm3

(c) 46.5 cm3

(d) 47.5 cm3

1 Answer

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Best answer

Correct option is (b) 93 cm3

According to boyle's law At constant temperature

\(P \propto \frac 1V\)

PV = Constant

P1V1 = P2V2

Given

P1 = 9.962 × 10N/m2

V1 = 95cm3

P2 = 10.13 × 10N/m2

V2\(\frac{95 \times 9.962\times 4}{10.13 \times 10^4}\) = 93.42 cm3

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