Correct option is (b) 64 min
Rate of diffusion of gases is:
\(\frac{Rate_1}{Rate_2} = \frac{\sqrt{M_2}}{\sqrt{M_1}}\)
Rate of H2 = \(\frac{50}{20} = 2.5\)
Rate of O2 = \(\frac{40}{t}\)
\(\mathrm{\frac{Rate\ of\ H_2}{Rate \ of \ O_2}} = \frac{2.5}{40/t}= \sqrt{\frac{MO_2}{MH_2} } = \sqrt{\frac{32}2} = \sqrt {16} = 4\)
∴ 2.5t = 160
∴ t = \(\frac{160}{2.5}\) = 64 mins