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On complete combustion of gaseous mixture of propane and butane, 10L CO2 is formed. Calculate the composition of gaseous mixture.

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Suppose, volume of propane in mixture = xL 

Volume of butane in mixture = (3 - x) L 

On complete combustion of gaseous

1L C3Hg gives CO2 = 3 L. 

x L C3H8 gives CO2 = 3x L 

Volume of butane in mixture

1L C4H10 give CO2 = 4L 

(3 - x) LC4H10 gives CO2 = 4 × (3 - x) L 

Volume of free CO2 = 10 L 

3x + 4(3 - x) = 10 

3x + 12 4x = 40 

- x = 10 -12 

x = 2 

Volume of propane = 2 L 

Volume of butane = (3 - 2) = 1L

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