In H-atom the energy of nth Bohr's orbit is: (a) -13.6/n^2 eV (b) -13.6/n eV

Question

In H-atom the energy of nth Bohr's orbit is: 

\((a)\ \frac{-13.6}{n^2}e V\)

\((b)\ \frac{-13.6}{n}eV\)

\((c)\ \frac{-13.6}{n^4}eV\)

\((d) \ \frac{-13.6}{n^3}eV\)

Answer 1

Correct option is : \((a)\ \frac{-13.6}{n^2}e V\)