If θ is argument of 3+2i/3-2i, then tan θ equals: (a) 6/13

Question

If θ is argument of \(\frac{3 + 2i}{3-2i}\), then tan θ equals:

(a) \(\frac{6}{13}\)

(b) \(\frac{12}{5}\)

(c) \(\frac{5}{13}\)

(d) None of these

Answer 1

Correct option is (b) \(\frac{12}{5}\)