Question

A-2. A sample of gas at \( 27^{\circ} C \) and 1.00 atm pressure occupies 2.50 L . What temperature is required to adjust the pressure of that gas to 1.50 atm after it has been transferred to a 2.00 L container?

Answer 1

equation i:-
PV=nRT
where P=1 atm
V=2.5L
T= 27C = 300K
1*2.5=nR*300
equation ii:-
PV=nRT
where P=1.5
V=2
T=x
1.5*2=nR*x
dividing equation i and ii we get
(1*2.5)/(1.5*2)= (nR*300)/(nR*x)
2.5/3=300/x
x=900/2.5
x=360k