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in Trigonometry by (20 points)
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Find the Range of y = 3sinx.

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2 Answers

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by (18.5k points)

The range of the function y = 3sin(x) is -3 <= y <= 3 because the function sin(x) varies between -1 and 1, which when multiplied by 3 gives a range from -3 to 3.

The range of the function y = 3sin(x) is given by -3 <= y <=3. This is because the sine function, sin(x), oscillates between -1 and 1 for all values of x. When you multiply this by 3, as in 3sin(x), the result will oscillate between -3 and 3.

This represents the highest and lowest values (antinodes) that the function 3sin(x) will yield, for any real number x, hence giving the range of the function y = 3sin(x).

0 votes
by (55 points)

As we know, \(\sin(x) \in [-1, 1]\), for all \(x\)

So, \(3 \sin(x) \in [-3, 3]\)

Range of \(y = 3 \sin(x)\) is \([-3, 3]\)

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