Question

An emf of 96.0 mV is induced in the windings of a coil when the current in a nearby coil is increasing at the rate of 1.20 A/s. What is the mutual inductance (M) of the two coils?

Answer 1

Given:

e = 96 mV = 96 × 10^-3 V, 

\(\frac{dl}{dt}\) = 1.20 A/s

To find: Mutual Inductance (M)

Formula: M = \(\frac{|e|}{|dl/dt|}\)

Calculation:

From formula

\(M = \frac{96 \times 10^{-3}}{1.2}\)

=80 × 10^-3

= 80 mH

Mutual Inductance of the two coils is 80 mH.