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A 10-kilogram block is pushed along a rough horizontal surface by a constant horizontal force F as shown. At time t = 0, the velocity v of the block is 6.0 meters per second in the same direction as the force. The coefficient of sliding friction is 0.2. Assume g = 10 meters per second squared.

 

a. Calculate the force F necessary to keep the velocity constant. 

The force is now changed to a larger constant value F'. The block accelerates so that its kinetic energy increases by 60 joules while it slides a distance of 4.0 meters. 

b. Calculate the force F'. 

c. Calculate the acceleration of the block.

1 Answer

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(a) constant velocity means 

Fnet = 0, 

F – fk = ma

F – µkmg = 0

F – (0.2)(10)(10) = 0 

F = 20 N

(b) A change in K would require net work to be done. By the work–energy theorem:

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