Question

The phase difference between displacement and acceleration of a particle in a simple harmonic motion is :

Answer 1

The correct option is C π

SHM is represented by x=Asinωt

Then, the velocity and acceleration after differentiation will be

v=Aωcosωt

a=−Aω2sinωt

Now, we see displacement is in sinωt & velocity is in cosωt

⇒ Phase difference between x & v=π/2 rad

Similarly, we see velocity in cosωt & acceleration in sinωt

⇒ Phase difference between v & a=π/2rad

Thus, we can conclude that the phase difference between x & a=π rad.