Correct option is (2) \(\frac{3}{8}\)
\(|A|=\left|\begin{array}{ll}a_{11} & a_{12} \\ a_{21} & a_{22}\end{array}\right|\)
\(=a_{11} a_{22}-a_{21} a_{12}\)
\(=\{-1,0,1\}\)

\(\therefore \operatorname{var}(\mathrm{x})=\sum \mathrm{P}_{\mathrm{i}} \mathrm{X}_{\mathrm{i}}{ }^{2}-\left(\sum \mathrm{P}_{\mathrm{i}} \mathrm{X}_{\mathrm{i}}\right)^{2}\)
\(=\frac{3}{8}-0=\frac{3}{8}\)