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A container of fixed volume contains a gas at \(27^{\circ} \mathrm{C}.\) To double the pressure of the gas, the temperature of gas should be raised to _______ \({ }^{\circ} \mathrm{C}.\)

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Answer is: 327 

\(V=\text { constant }\)  

\(\frac{P_1}{T_1} =\frac{P_2}{T_2} \)

\(P_2 =2 P_1 \)

\(T_2 =2 T_1 \)

\(=2 \times 300=600 \mathrm{~K} \)

\(\therefore \ =327^{\circ} \mathrm{C}\)

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