Correct option is : (B) 7.07 A
The peak value \((I_0)\) of the alternating current is given as 10 A.
The RMS value \((I_{rms})\) of an alternating current is related to its peak value by the formula:
\(I_{rms} = \frac{I_0}{\sqrt{2}}\)
where \(I_0\) is the peak value.
Now, substitute the given peak value into the formula:
\(I_{rms} = \frac{10\ A}{\sqrt{2}}\)
To calculate \(\frac{10}{\sqrt{2}}\)
\(I_{rms} = \frac{10}{1.414}\approx7.07\ A\)
