Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
115 views
in Physics by (44.2k points)
closed by

Dimensional formula of permeability is  

(A) \([MLT ^ {- 2} A ^{ - 2}]\)

(B) \([MLT ^ 2 A ^ {- 2}]\)

(C) \([MLT ^ 2 A ^ 2]\)

(D) \([ML T ^{ - 2} A]\)

2 Answers

+1 vote
by (74.8k points)
selected by
 
Best answer

Correct option is : (A) \([MLT ^ {- 2} A ^{ - 2}]\)

The permeability of free space (vacuum permeability) is a physical constant denoted by \(\mu_0\). It is defined as the measure of the ability of a material to support the formation of a magnetic field within itself. The dimensional formula of permeability can be derived from the relationship between magnetic field (B), magnetic field strength (H), and permeability \((\mu)\). The relationship is given by \(B = \mu H\). The dimensional formula of B is \([MT^{-2}I^{-1}]\) and H is \([I \ L^{-1}]\). Therefore, the dimensional formula of μ is obtained by dividing the dimensional formula of B by the dimensional formula of H.

+1 vote
by (44.6k points)
edited by

Correct option is (A) \([MLT ^ {- 2} A ^{ - 2}]\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...