Question

The zeroes of the polynomial \(2x^2 - 4x - 6\) are

(A) 1, 3

(B) -1, 3

(C) 1, -3

(D) -1, -3

Answer 1

Correct option is: (B) -1, 3

\(2 x^2-4 x-6 =0 \)

\(2 x^2-6 x+2 x-6 =0\)

\(2 x(x-3)+2(x-3) =0 \)

\((x-3)(2 x+2) =0 \)

\(x-3=0 \quad \text { or } \quad 2 x+2 =0 \)

\(x=3 \quad \text { or } \quad 2 x =-2 \)

\(x =\frac{-2}{2} \)

x = -1

Zeroes = -1, 3

Answer 2

Correct option is: (B) -1, 3