Question

If p + 1, 3P + 1, 6P - 1 are in A.P. then the value of P is

(A) 1

(B) 2

(C) 3

(D) 4

Answer 1

Correct option is: (B) 2  

Given:-

\(p+1,\ 3 p+1,\ 6 p-1 \text { are in A.P. }\)

we know that.

\(a_2-a_1 =a_3-a_2 \)

\((3 p+1)-(p+1) =(6 p-1)-(3 p+1) \)

\(3 p+1-p-1 =6 p-1-3 p-1 \)

\(2 p =3 p-2 \)

\(2 p-3 p =-2 \)

\(-p =-2 \)

\(\therefore p =2\)  

Answer 2

Correct option is: (B) 2