यदि tan θ = 12/5 हो तो cos θ का मान है ​(A) 5/12 (B) 5/13 (C) 13/5 (D) 12/13

Question

यदि \(tan\ \theta = \frac{12}{5}\) हो तो \(cos \ \theta\) का मान है

(A) \(\frac{5}{12}\)

(B) \(\frac{5}{13}\)

(C) \(\frac{13}{5}\)

(D) \(\frac{12}{13}\)

Answer 1

सही विकल्प है: (B) \(\frac{5}{13}\) 

Given:-

\(\tan \theta = \frac{12}{5}\) 

\(\tan \theta=\frac{\text{perpendicular}}{\text{Base}} = \frac{12}{5}\)  

By pythagorean theorem:- 

\(H^2 = P^2+ B^2\)  

\(= (12)^2 + (5)^2\) 

= 144 + 25 

= 169 

\(= \sqrt{169} ​\)

= 13 

\(\therefore \cos \theta = \frac{\text{adjacent/Base}}{\text{Hypotenuse}}\)

\(=\frac{5}{13}\)

Answer 2

सही विकल्प है: (B) \(\frac{5}{13}\)