cos 49° / sin 41° × tan 70° / cot 20° = (A) -1 (B) 0 (C) 1 (D) 2

Question

\(\frac{cos \ 49^\circ}{sin \ 41^\circ} \times \frac{tan \ 70^\circ}{cot \ 20^\circ}=\)

(A) -1

(B) 0

(C) 1

(D)  2

Answer 1

Correct option is: (C) 1  

\(\frac{\cos 49^\circ}{\sin 41^\circ } \times \frac{\tan 70^\circ}{\cot 20^ \circ}\)  

\(= \frac{\cos (90^\circ-41^\circ)}{\sin 41^\circ} \times \frac{\tan(90^\circ-20^\circ)}{\cot20^\circ}\) 

\(= \frac{\sin 41^\circ}{\sin 41^\circ} \times \frac{\cot 20^\circ}{\cot 20^\circ}\)  

\(= 1 \times 1\)  

= 1

Answer 2

Correct option is: (C) 1