Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
27 views
in Chemistry by (21.4k points)

An octahedral complex ion is formed using metal (M4+) with ligands NH3 and Cl 1 mol complex gives ‘n’ mol of AgCl with AgNO3 solution. The value of n is same as number of lone pairs of electron present on central atom in BrF3. Find the total number of isomers of complex ion.

Please log in or register to answer this question.

1 Answer

0 votes
by (20.8k points)

Answer is : (2)

number of lone pair = 2

AgNO3 + Complex → 2 mol AgCl

Complex ion should be [M(NH3)4Cl2]Cl2

Total number of isomers = 2

Total number of isomers = 2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...