Question

Find the mass of CaO formed in kg when 150 kg sample of 75% pure CaCO₃ is heated strongly.

Answer 1

Answer is : (63)

Mass of impure CaCO₃ = 150 kg

\(\text{Mass of pure CaCO}_3 = \frac{75\times150}{100} = 112.5 \ \text{kg}\)

\(\text{NO. of moles of pure CaCO}_3 = \frac{112.5 \times 10^3}{100}\)

= 1125

\(\text{CaCO}_3 \xrightarrow {\Delta} \text{Cao} + \text{Co}_2\ \text{(g)}\)

No. of moles of CaO formed = 1125

\(\text{Mass of CaO} = \frac{1125\times 56}{1000} = 63 \ \text{kg}\)