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In Dumas method, 292 mg of organic compound yields 50 mL N2(g) at 300 K and 715 mm Hg pressure. Find % of ‘N’ in organic compound. Aqueous tension i = 15 mm Hg

Aqueous tension i = 15 mm Hg

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Answer is : (18)

\(V_{N_2} \ \text{at STP} = \frac{273 \times (715- 15)\times 50}{300\times 760}\)

\(= 41.9 \ \text{ml}\)

\(m _{n_2} = \frac{41.9}{22400} \times 28 = 0.052 \ g\)

\(\%\ \text{of N} = \frac{0.052 \ g}{0.292} \times 100 = 17.94 \% \)

\(\simeq 18 \% \)

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