Question

If a charged particle is projected in a uniform magnetic field perpendicular to its velocity then the minimum time in which it returns to its original position:-

(1) \(\frac{2\pi m}{qB}\)

(2) \(\frac{\pi m}{qB}\)

(3) \(\frac{qB}{2\pi m}\)

(4) None

Answer 1

Correct option is : (1) \(\frac{2\pi m}{qB}\) 

\(t_{min} = T = \frac{2\pi m}{qB}\)