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in Mathematics by (44.8k points)

Line \(L_{1}\) of slope 2 and line \(L_{2}\) of slope \(\frac{1}{2}\) intersect at the origin O . In the first quadrant, \(\mathrm{P}_{1}, \mathrm{P}_{2}, \ldots . \mathrm{P}_{12}\) are 12 points on line \(L_{1}\) and \(\mathrm{Q}_{1}, \mathrm{Q}_{2}, \ldots . . \mathrm{Q}_{9}\) are 9 points on line \(L_{2}.\) Then the total number of triangles, that can be formed having vertices at three of the 22 points \(\mathrm{O}, \mathrm{P}_{1}, \mathrm{P}_{2}, \ldots \mathrm{P}_{12}, Q_{1}, Q_{2}, \ldots . Q_{9},\) is:

(1) 1080

(2) 1134

(3) 1026

(4) 1188 

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1 Answer

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by (44.4k points)

Correct option is: (2) 1134 

Total number of \(\Delta\) are

\(={ }^{9} \mathrm{C}_{1}{ }^{12} \mathrm{C}_{2}+{ }^{9} \mathrm{C}_{2}{ }^{12} \mathrm{C}_{1}+{ }^{1} \mathrm{C}_{1}{ }^{9} \mathrm{C}_{1}{ }^{12} \mathrm{C}_{1}\)

= 594 + 432 + 108

= 1134  

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