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ago in Chemistry by (43.9k points)

Match the LIST-I with LIST-II

LIST-I (Complex/Species) LIST-II (Shape & magnetic moment)
A. \([Ni(CO)_4]\) I. Tetrahedral, 2.8 BM
B. .\([Ni(CN)_4]^{2-}\) II. Square planar, 0 BM
C. \([NiCl_4]^{2-}\) III. Tetrahedral, 0 BM
D. \([MnBr_4]^{2-}\) IV Tetrahedral, 5.9 BM

Choose the correct answer from the options given below : 

(1) A - III, B - IV, C - II, D - I 

(2) A - I, B - II, C - III, D - IV 

(3) A - III, B - II, C - I, D - IV 

(4) A - IV, B - I,  C - III, D

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1 Answer

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ago by (43.7k points)

Correct option is: (3) A - III, B - II, C - I, D - IV 

(A)  \([Ni(CO)_4], \ Ni^0 : [Ar]3d^8 \ 4s^2 \)

Valence orbitals of \(Ni^0\) in pre-hybridisation state:

Tetrahedral

Tetrahedral , Diamagnetic , \(\mu = 0 \ B.M.\)

(B) \([NiCl_4]^{2-} , Ni^{2+} : [Ar]3d^84s^0\)

Valence orbitals of \(Ni^{+2}\) in pre-hybridisation state:

square planar

Square planar, Diamagnetic , \(\mu = 0 \ B.M.\)

(C) \([NiCl_4]^{2-}, Ni^{+2}:[Ar]3d^84s^0\)

Valence orbitals of \(Ni^{+2}\) in ground state:

Tetrahedral

Tetrahedral, paramagnetic , \(\mu = \sqrt{8} = 2.8 \ B.M.\)

(D) \([MnBr_4]^{2-}, Mn^{+2} : [Ar]3d^5\)

Valence orbitals of \(Mn^{+2}\) in ground state:

tetrahedral

Tetrahedral, paramagnetic , \(\mu = \sqrt{35}= 5.9 \ B.M.\)

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