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The emf of a Daniell cell at 298 K is E1 Zn | ZnSO4(0.01 M) || CuSO4 (1.0 M) | Cu When the concentration of ZnSO4 is 1.0 M and that of CuSO4 is 0.01 M, the emf is changed to E2. What is the relationship between E1 and E2

(a) E2 = 0 | E1 

(b) E1 > E2 

(c) E1 < E2 

(d) E1 = E2

1 Answer

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Best answer

Correct option (b)

Explanation:

Daniell cell reaction :

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