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If the principle argument of a complex number (–1 + i)^50 is nπ/2

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If the principle argument of a complex number (–1 + i)50 is nπ/2 and the equation z2 – az + b + 2i = 0 has one real root. If a = (1 + i)–n and b ∈R, then other root of given equation is

(a) 1

(b) – 1

(c) 1 + i

(d) – 1 + i

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Correct option (d)

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