The given equation (D2 – 2D – 3)y = 3e2x … (1)
has auxiliary equation as: D2 – 2D – 3 = 0
or D = 3, – 1 .…(2)
Thus the complementary function, C.F. = c1e3x + c2e–x … (3)
For particular integral,
P.I = 1/D2 - 2D - 3e2x(comparable to 1/f(D) eax = eax/f(a), f(a) ≠ 0)
= 3/(2)2 - 2(2) - 3 e2x = -e2x
Whence the complete solution, y = (c1e3x + c2e-x) - e-2x