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A 500N cylinder, 1 m in diameter is loaded between the cross pieces AE and BD which make an angle of 60º with each other and are pinned at C. Determine the tension in the horizontal rope DE assuming that the cross pieces rest on a smooth floor.

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Consider the equilibrium of the entire system. 

C is the pin joint, making the free body diagram of ball and rod separately. 

2RN cos 60° = 500 ...(i) 

RN = 500K N 

RA + RB = 500 N ...(ii) 

Due to symmetry RA = RB = 250 N 

CP = 0.5 cot 30° = 0.866 m

Taking moment about point C

T × 1.8 cos 30° – RN × CP – RB × 1.2 sin 30° = 0

T × 1.8 cos 300 = RN × CP + RB × 1.2 sin 30°

Putting the value of CP, RN, and RB

T = 374N.

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