Hinged at A and Roller at B, FBD of the beam is as shown in fig,
∑H = 0
RAH –5000 cos 30° = 0
RAH = 4330.127N
∑V = 0
RAV + RBV –5000 sin 30° = 0
RAV + RBV = 2500 N ........(i)
Taking moment about point B:
∑MB = RAV × 5 – 5000 sin 30° × 2.5 = 0
RAV = 1250 N
From equation (i)
RBV = 1250 N.
