Question

Calculate the binding energy per nucleon ⁴⁰₂₀Ca nucleus.

[Given : m ⁴⁰₂₀( Ca) ] = 39.962589 u 

m_n (mass of a neutron) = 1.008665 u

m_p (mass of a proton) = 1.007825 u 

1 u = 931 MeV/c² ]

Answer 1

Total Binding energy of ⁴⁰₂₀Ca nucleus

= 20m_p + 20 m_n – M ( ⁴⁰₂₀Ca)

= 20 × 1.007825 + 20 × 1.008665 – 39.962589

= 0.367211 u = 0.367211 × 931 MeV = 341.87 Mev

∴ Binding energy per nucleus = 341.87/40 MeV/nucleon

= 8.55 MeV/nucleon