The A.M. of the given data

The absolute values of the deviations are
|6 – 10|, |7 – 10|, |10 – 10|, |12 – 10|, |13 – 10|, |4 – 10|, |12 10|, |16 – 10|
= 4, 3, 0, 2, 3, 6, 2, 6
∴ The mean deviation from the mean

= 1/8(4 + 3 + 0 + 2 + 3 + 6 + 2 + 6)
= 26/8 = 3.25