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Explain the reaction of the following with water.

(a) XeF2

(b) XeF4

(c) XeF6

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(a) XeF2 is hydrolysed to form Xe, HF and O2

2XeF2 + 2H2O → 2Xe + 4HF + O2

(b) XeF4 is hydrolysed to give XeO3

6XeF4 + 12H2O → 4Xe + 2XeO3 + 24HF + 3O2

(c) XeF6 undergo hydrolysis to form XeO3

XeF6 + 3H2O → XeO3 + 6HF

XeF6 undergo partial hydrolysis to form XeOF4 + XeO2F2

XeF6 + H2O → XeOF4 + 2HF

XeF6 + 2H2O → XeO2F2 + 4HF

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