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Find the slope of the tangent to the curve y = x^3 + 3x^2 + 3x – 10 at x = 2.

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in Limit, continuity and differentiability by (50.4k points)

Find the slope of the tangent to the curve y = x3 + 3x2 + 3x – 10 at x = 2.

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1 Answer

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Best answer

The given curve is

y = x3 + 3x2 + 3x – 10

dy/dx = 3x3 + 6x + 3

Thus, m = (dy/dx)x=2

= 3.4 + 6.2 + 3 = 27

Hence, the slope of the tangent is 27.

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