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Find the slope of the normal to the curve y = x^x + 1 at x = 2

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in Limit, continuity and differentiability by (50.4k points)

Find the slope of the normal to the curve y = xx + 1 at x = 2

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Best answer

The given curve is y = xx + 1

dy/dx = xx(logx + 1)

Thus, m = ( dy/dx)x=2 = 22(log2 + 1)

= 4(log 2 + 1)

Hence, the slope of the normal is = –  1/4(log2 + 1)

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